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Without performing actual computations, find the quotient when $94 - 49$ is divided by
(i) 9.
(ii) 5.
Given:
$94 - 49$
To do:
We have to find the quotient when $94 - 49$ is divided by
(i) 9.
(ii) 5.
Solution:
(i) We know that when $ab-ba$ is divided by $9$ then the quotient is $(a-b)$.
The digits of the given numbers 94 and 49 are reversed.
Here,
$a = 9, b = 4$
$a-b=9-4=5$
If $94 -49$ is divided by $9$, then the quotient is $a-b=5$.
(ii) We know that when $ab-ba$ is divided by $(a-b)$ then the quotient is $5$.
The digits of the given numbers 94 and 49 are reversed.
Here,
$a = 9, b = 4$
$a-b=9-4=5$
If $94 -49$ is divided by $5$, then the quotient is $9$.
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