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Which of the following is greater: $\frac{-11}{28}$ or $\frac{29}{-42}$.
Given: Fractions: $\frac{-11}{28}$ and $\frac{29}{-42}$.
To do: To find the greater fraction.
Solution:
Given fractions: $\frac{-11}{28}$ and $\frac{29}{-42}$.
We can write the given fraction as $-\frac{11}{28}$ and $-\frac{29}{42}$. To compare the given fractions we have to equalize both the fraction.
On taking L.C.M. of the denominators of the given fractions:-
$28=2\times2\times7$
$42=2\times3\times7$
L.C.M. of $28$ and $42=2\times2\times3\times7=84$
Thus, $-\frac{11}{28}=-\frac{11\times3}{28\times3}=-\frac{33}{84}$
$-\frac{29}{42}=-\frac{29\times2}{42\times2}=-\frac{58}{84}$
On comparing both the fractions,
$-\frac{58}{84}<-\frac{33}{84}$
$\Rightarrow -\frac{29}{42}<-\frac{11}{28}$
$\Rightarrow \frac{29}{-42}<\frac{-11}{28}$
Thus, fraction $\frac{-11}{28}$ is greater than $\frac{29}{-42}$.