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Which of the following are quadratic equations?
$2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$
Given:
Given quadratic equation is $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$.
To do:
We have to check whether the given equation is quadratic.
Solution:
The standard form of a quadratic equation is $ax^2+bx+c=0$.
$2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$
The equation $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$ is not of the form $ax^2+bx+c=0$ as the power of $\sqrt{3x}$ is not an integer.
Therefore, $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$ is not a quadratic equation.
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