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What should be taken away from (6m2 $-$ 4n2 $+$ 3mn $+$ 15) to obtain ($-$m2 $-$ n2 $+$ 3mn $+$ 15)?
Given: (6m2 $-$ 4n2 $+$ 3mn $+$ 15) and ($-$m2 $-$ n2 $+$ 3mn $+$ 15).
To find: What should be taken away from (6m2 $-$ 4n2 $+$ 3mn $+$ 15) to obtain ($-$m2 $-$ n2 $+$ 3mn $+$ 15)?
Solution:
Let the required value be = a
So,
(6m2 $-$ 4n2 $+$ 3mn $+$ 15) $-$ a = ($-$m2 $-$ n2 $+$ 3mn $+$ 15)
(6m2 $-$ 4n2 $+$ 3mn $+$ 15) $-$ ($-$m2 $-$ n2 $+$ 3mn $+$ 15) = a
6m2 $-$ 4n2 $+$ 3mn $+$ 15 $+$ m2 $+$ n2 $-$ 3mn $-$ 15 = a
7m2 $-$ 3n2 = a
Therefore, (7m2 $-$ 3n2) should be taken away from (6m2 $-$ 4n2 $+$ 3mn $+$ 15) to obtain ($-$m2 $-$ n2 $+$ 3mn $+$ 15).
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