![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
What should be taken away from $3x^2-4y^2+5xy+20$ to obtain $– x^2-y^2+6xy+20$?
Given: Terms $3x^2-4y^2+5xy+20$ and $– x^2-y^2+6xy+20$.
 
To do: This is to find out what should be taken from $3x^2-4y^2+5xy+20$ to get $- x^2-y^2+6xy+20$.
Solution: Let us assume $a$ be the required term
Then,
$3x^2-4y^2+5xy+20-a=-x^2-y^2+6xy+20$
$a=3x^2-4y^2+5xy+20-(-x^2-y^2+6xy+20)$
$a=3x^2-4y^2+5xy+20+x^2+y^2-6xy-20$
$a=3x^2+x^2-4y^2+y^2+5xy-6xy+20-20$
$a=4x^2-3y^2-xy$
Therefore, $4x^2-3y^2-xy$ should be taken from $3x^2-4y^2+5xy+20$ to get $- x^2-y^2+6xy+20$.
Advertisements