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What should be added to $ \left(\frac{-13}{4}+\frac{-3}{8}\right) $ to get $ 1 ? $
Given:
$\frac{-13}{4}+\frac{-3}{8}$.
To do:
We have to find the number that should be added to $\frac{-13}{4}+\frac{-3}{8}$ to get 1.
Solution:
Let the required number be $x$.
This implies,
$\frac{-13}{4}+\frac{-3}{8}+x=1$
$\frac{2(-13)+(-3)}{8}+x=1$ (LCM of 4 and 8 is 8)
$\frac{-26-3}{8}+x=1$
$\frac{-29}{8}+x=1$
$x=1-(\frac{-29}{8})$
$x=1+\frac{29}{8}$
$x=\frac{1\times8+29}{8}$
$x=\frac{8+29}{8}$
$x=\frac{37}{8}$
The number that should be added to $\frac{-13}{4}+\frac{-3}{8}$ to get 1 is $\frac{37}{8}$.
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