What is the probability that an ordinary year has 53 Sundays?

Given:

An ordinary year which has 53 Sundays

To do:

We have to find the probability that an ordinary year has 53 Sundays.

Solution:

There are 365 days in an ordinary year which has 52 weeks and 1 day.

This implies the extra day can be any day from Monday to Sunday.

If the year has 53 Sundays then it implies that the extra day is a Sunday.

The total number of possible outcomes $n=7$

Total number of favourable outcomes $=1$

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

The probability that an ordinary year has 53 Sundays $=\frac{1}{7}$

The probability that an ordinary year has 53 Sundays is $\frac{1}{7}$.

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Updated on: 10-Oct-2022

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