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What is the probability that a leap year has 53 Tuesdays and 53 Mondays?
Given:
A leap year has 53 Tuesdays and 53 Mondays.
To do:
We have to find the probability that a leap year has 53 Tuesdays and 53 Mondays.
Solution:
There are 366 days in a leap year which has 52 weeks and 2 days.
This implies the 2 extra days can be any days from Monday and Tuesday to Sunday and Monday.
If the year has 53 Mondays and 53 Tuesdays then it implies that the 2 extra days are Monday and Tuesday.
The total number of possible outcomes $n=7$
Total number of favourable outcomes $=1$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
The probability that a leap year has 53 Tuesdays and 53 Mondays $=\frac{1}{7}$
The probability that a leap year has 53 Tuesdays and 53 Mondays is $\frac{1}{7}$.