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What is the perimeter of a rectangle of length 65 cm and breadth 55 cm?
Given :
The length of the rectangle (l) $= 65\ cm$.
The breadth of the rectangle (b) $=55\ cm$.
To do :
We have to find the perimeter of the rectangle.
Solution :
The perimeter of the rectangle with length 'l' and breadth 'b' is given by $2(l+b)$.
Perimeter$= 2(65+55)$
$=2(120)$
$ = 240\ cm$
Therefore, the perimeter of the rectangle is 240 cm.
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