What is the measure of $\angle P$ in the given figure, when $\angle d = 2\angle P$?
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Given:
$\angle d = 2\angle P$.
To do:
We have to find the measure of $\angle P$.
Solution:
In the given figure,
$\angle d + \angle P = 90^o$
$2\angle P + \angle P = 90^o$ (given $\angle d = 2\angle P$)
$3\angle P = 90^o$
$\angle P = \frac{90^o}{3}$
$\angle P = 30^o$
The measure of $\angle P$ is $30^o$.
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