What is the area of cross-section of a wire if its length is 2 m, resistance is 46 Ω and resistivity is 1.84 X 10 ^-6 Ω m?

Given: Resistivity is 1.84 X 10 ^-6 Ω m, Length is 2m, Resistance is 46 Ω

To find: Area of cross section

Solution:

We know the formula:

$Resistance \ R = \frac{\rho \times L}{A} $

So,

$Area\ of\ cross section\ A= \frac{\rho \times L}{R} $

$= \frac{1.84 \times 10^{-6} \times 2}{46} $

$= \frac{184\times 2}{46}  \times 10^{-8}  $

$= 8 \times 10^{-8} m^{2} $

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Updated on: 10-Oct-2022

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