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What force acting on an area of $8\ m^2$ will produce a pressure of $40\ Pa$?
Given:
Area $A=8\ m^2$
Pressure $P=40\ Pa$
Let $F$ be the acting force.
We know, $Pressure\ P=\frac{Force(F)}{Area(A)}$
Or $40=\frac{F}{8}$
Or $F=40\times8$
Or $F=320\ N$
Therefore, $320\ N$ is the acting force on the given area.
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