What are the roots of $x^2-16 =0$?
Given: Equation $x^2-16 =0$.
To do: To find the root of $x^2-16 =0$.
Solution:
$x^2-16 =0$
$\Rightarrow x^2-4^2$
$\Rightarrow ( x-4)( x+4)=0$
If $x-4=0\Rightarrow x=4$
If $x+4=0\Rightarrow x=-4$
Thus, $x=-4,\ 4$.
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