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What are the factors of $4x(3y-x)+y(3y-x)$.
Given:
$4x(3y-x)+y(3y-x)$.
To do:
We have to find the factors of $4x(3y-x)+y(3y-x)$.
Solution:
Taking $3y-x$ common, we get,
$4x(3y-x)+y(3y-x)=(4x+y)(3y-x)$
Therefore,
Factors of $4x(3y-x)+y(3y-x)$ are $4x+y$ and $3y-x$.
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