Verify whether the indicated numbers are zeros of the polynomials corresponding to them in the following cases:
\( f(x)=3 x+1, x=-\frac{1}{3} \)
Given:
\( f(x)=3 x+1, x=-\frac{1}{3} \)
To do:
We have to find whether the indicated numbers are zeros of the polynomials corresponding to them.
Solution:
To find whether $x=-\frac{1}{3}$ is a zero of $f(x)$ we have to check if $f(-\frac{1}{3})=0$.
Therefore,
$f(-\frac{1}{3})=3(-\frac{1}{3})+1$
$=-1+1$
$=0$
Therefore, $x=-\frac{1}{3}$ is the zero of $f(x)$.
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