Verify whether the indicated numbers are zeros of the polynomials corresponding to them in the following cases:
\( f(x)=2 x+1, x=\frac{1}{2} \)
Given:
\( f(x)=2 x+1, x=\frac{1}{2} \)
To do:
We have to find whether the indicated numbers are zeros of the polynomials corresponding to them.
Solution:
To find whether $x=\frac{1}{2}$ is a zero of $f(x)$ we have to check if $f(\frac{1}{2})=0$
Therefore,
$f(\frac{1}{2})=2 \times(\frac{1}{2})^{2}+1$
$=2 \times \frac{1}{4}+1$
$=\frac{1}{2}+1$
$=\frac{3}{2}$
Therefore, $x=\frac{1}{2}$ is not a zero of $f(x)$.
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