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Using distributivity, find:
$\frac{8}{15} \times \frac{-7}{18} + \frac{8}{15} \times \frac{-11}{18} $
Given:$\frac{8}{15} \times \frac{-7}{18} + \frac{8}{15} \times \frac{-11}{18} $
To Do: Using distributive law solve the following question
Solution
Distributive property of multiplication states that
a x b + a x c = a (b + c)
for any three numbers a, b, c
= $ \frac{-7}{18} \frac{-11}{18}$
= $\frac{8}{15} \times \frac{-7-11}{18}$
= $\frac{8}{15} \times \frac{-18}{18}$
= $\frac{8}{15} \times \frac{-1}{1}$
= Therefore the solution is -$\frac{8}{15}$
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