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Two supplementary angles differ by $48^o$. Find the angles.
Given:
Two supplementary angles differ by $48^o$.
To do:
We have to find the measure of the angles.
Solution:
Two angles are said to be supplementary if the sum of their measures is $180^o$.
Let the required angles be $x$ and $x+48^o$.
Therefore,
$x+(x+48^o)=180^o$
$2x=180^o-48^o$
$x=\frac{132^o}{2}$
$x=66^o$
This implies,
$x+48^o=66^o+48^o=114^o$
The measures of the required angles are $66^o$ and $114^o$.
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