Two men start from points $A$ and $B$ respectively, $42\ km$ apart. One walks from $A$ to $B$ at $4\ km/hr$ and another walks from $B$ to $A$ at a certain uniform speed. They meet each other after 6 hours. Find the speed of the second man.

Given: Two men start from points $A$ and $B$ respectively, $42\ km$ apart. One walks from $A$ to $B$ at $4\ km/hr$ and another walks from $B$ to $A$ at a certain uniform speed. They meet each other after 6 hours.

To do: To find the speed of the second man.

Solution:

As given, distance between $A$ and $B=42\ km$

One person walks from $A$ to $B$ at the speed of $4\ km/hr$

Another person walks from $B$ to $A$ at a certain uniform speed.

They meet each other after $6$ hours .

Distance traveled by first person in $6$ hours$=speed\times time=4\times6=24\ km$

$\therefore$ The distance traveled by first from Point $A=24\ km$

$\therefore$ Remaining distance $=42-24=18\ km$

A person who walks from point $B$ has traveled $18\ km$ till the point where they meet.

$\therefore$ Distance traveled by second person in $6$ hours$=18\ km$

$\therefore$ Speed of second person$=\frac{distance}{time}$

$=\frac{18}{6}$     

$=3$     

Thus, the speed of second person is $3\ km/hr$.

Updated on: 10-Oct-2022

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