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Two dice are thrown together. The probability of getting the same number on both dice is:
$( A)\ \frac{1}{2}$
$( B)\ \frac{1}{3}$
$( C)\ \frac{1}{6}$
$( D)\ \frac{1}{12}$
Given: Two dice are thrown together.
To do: to find out the probability of getting the same number on both dice.
Solution: we know that a dice has six sides with number 1 to 6.
And when a dice is thrown there are 6 possible outcomes and when two dice are thrown together there are $6x6 =36$ possible outcomes.
And here our favourable outcomes are, {$( 1,\ 1) ,\ ( 2,\ 2) ,\ ( 3,\ 3) ,\ ( 4,\ 4) ,\ ( 5,\ 5) ,\ ( 6,\ 6)$}
probability of getting the same number on both dice$=\frac{no.of favourable outcomes}{total possible outcomes}$
$=\frac{6}{36}$
$=\frac{1}{6}$
$\therefore$ Option $( C)$ is correct.
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