- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Today Ramu's age is $\frac{1}{2}$ times of his father's age Ramu's mother is 25 years older than Ramu. Difference between the age of his parents is 5 years. How old is everyone in his family?
Given: Ramu's age is $\frac{1}{2}$ times of his father's age. Ramu's mother is 25 years older than Ramu. Difference between the age of his parents is 5 years.
To find: Here we have to find the present age of Ramu's family.
Solution:
Let age of Ramu = a
Given that, Ramu's age is $\frac{1}{2}$ times of his father's age:
$\frac{1}{2}$(Age of Ramu's father) = Age of Ramu
Age of Ramu's father = 2(Age of Ramu)
Age of Ramu's father = 2a
Also, Ramu's mother is 25 years older than Ramu:
Age of Ramu's mother = Age of Ramu $+$ 25
Age of Ramu's mother = a $+$ 25
Now, difference between the age of his parents is 5 years:
Age of Ramu's father $-$ Age of Ramu's mother = 5
2a $-$ (a $+$ 25) = 5
2a $-$ a $-$ 25 = 5
a = 5 $+$ 25
a = 30
Therefore,
Age of Ramu = a = 30 years
Age of Ramu's father = 2a = 60 years
Age of Ramu's mother = a $+$ 25 = 55 years