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Three coins are tossed together. Find the probability of getting exactly two heads.
Given:
Three coins are tossed together.To do:
We have to find the probability of getting exactly two heads.
Solution:
When three coins are tossed, the total possible outcomes are HHH, HHT, HTH, THH, TTH, THT, HTT and TTT.
This implies,
The total number of possible outcomes $n=8$.
Number of outcomes where exactly two heads occur $=3$
Total number of favourable outcomes $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting exactly two heads $=\frac{3}{8}$
The probability of getting exactly two heads is $\frac{3}{8}$.
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