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Three coins are tossed together. Find the probability of getting at least one head and one tail.
Given:
Three coins are tossed together.To do:
We have to find the probability of getting at least one head and one tail.
Solution:
When three coins are tossed, the total possible outcomes are HHH, HHT, HTH, THH, TTH, THT, HTT and TTT.
This implies,
The total number of possible outcomes $n=8$.
Number of outcomes where at least one head and one tail occur $=6$
Total number of favourable outcomes $=6$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting at least one head and one tail $=\frac{6}{8}$
$=\frac{3}{4}$
The probability of getting at least one head and one tail is $\frac{3}{4}$.
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