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Three coins are tossed. Find the probability of getting atmost one head.
Given: Three coins are tossed.
To do: To find the probability of getting atmost one head.
Solution:
When three coins are tossed, outcomes are :-HHH, HHT, HTH, THH, TTT, TTH, THT, HTT.
\therefore Total possible outcomes$=8$
nomber of events of getting atmost head $=3$
The probability of getting atmost one head $=\frac{Total\ no.\ favorable\ outcomes}{Total\ no.\ possible\ outcomes}=\frac{3}{8}$
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