The Vertical Angle Of An Isosceles Triangle Is 100°. Find It's Base Angles.
The Vertical Angle Of An Isosceles Triangle Is 100°. Find It's Base Angles.
Solution:
In an isosceles triangle, base angles are equal. Let the base angles be x and x.
The vertical angle of the triangle = 100°
Sum of angles in the isosceles triangle = x + x + 100° = 180°
2x + 100° = 180°
2x = 180° - 100° = 80°
x = 80°/2 = 40°
So base angles of the isosceles triangle are 40°, 40°
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