The surface area of cube is \( 18 \frac{3}{8} m^{2} \). Find its volume.

Given:

The surface area of cube is \( 18 \frac{3}{8} m^{2} \).

To do:

We have to find its volume.

Solution:

We know that,

The surface area of a cube of side $a=6a^2$.

Let the side of the given cube be $s$.

This implies,

$6s^2=18\frac{3}{8}$

$6s^2=\frac{18\times8+3}{8}$

$6s^2=\frac{147}{8}$

$s^2=\frac{147}{48}$

$s=\sqrt{\frac{147}{48}}$

Volume of the cube$=s^3=s^2 \times s$

$=\frac{147}{48}\times\sqrt{\frac{147}{48}}$

$=\frac{147}{48}\sqrt{\frac{147}{48}}$.

The volume of the cube is $\frac{147}{48}\sqrt{\frac{147}{48}}$.

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Updated on: 10-Oct-2022

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