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The sum of three consecutive multiples of 7 is 63. Find multiples.
Given :
The sum of three consecutive multiples of 7 is 63.
To do :
We have to find the numbers.
Solution :
Let the three consecutive multiples be $7x,7x+7$, and $7x+14$.
Therefore,
$7x+7x+7+7x+14=63$
$21x+21=63$
$21x=63-21$
$21x=42$
$x=\frac{42}{21}$
$x=2$
The three consecutive numbers are $7(2)=14, 7(2)+7=14+7=21, 7(2)+14=14+14=28$.
Therefore, the three numbers are 14, 21, 28.
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