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The sum of three consecutive multiples of 2 is 18. Find the numbers.
Given: Sum of three consecutive multiples of 2 is 18.
To find: Here we have to find the numbers.
Solution:
Let the numbers be $x$, $x\ +\ 2$ and $x\ +\ 4$
Now,
$x\ +\ (x\ +\ 2)\ +\ (x\ +\ 4)\ =\ 18$
$3x\ +\ 6\ =\ 18$
$3x\ =\ 18\ -\ 6$
$x\ =\ \frac{12}{3}$
$\mathbf{x\ = 4}$
Therefore, the numbers are
$x\ =$ 4
$x\ +\ 2\ =$ 6
$x\ +\ 4\ =$ 8
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