The solution of the equation \( x-y=10 \) and \( x+y=70 \) is \( \ldots \)
A) \( (40,30) \)
B) (30,40)
C) \( (10,60) \)
D) \( (50,20) \)


Given:

The given pair of equations is \( x-y=10 \) and \( x+y=70 \).

To do:

We have to find the solution of the given system of equations.

Solution:

Adding the given equations, we get,

$(x-y)+(x+y)=10+70$

$x+x-y+y=80$

$2x=80$

$x=\frac{80}{2}$

$x=40$

Substituting $x=40$ in $x+y=70$, we get,

$40+y=70$

$y=70-40$

$y=30$

Therefore, the solution of the given system of equations is $(40, 30)$.

Updated on: 10-Oct-2022

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