The refractive index of water with respect to air is $\frac {4}{3}$. The refractive index of air with respect to water will be:(a) 1.75 (b) 0.50 (c) 0.75 (d) 0.25

(c) 0.75

Explanation

Given:

The refractive index of water with respect to air, $_{a}\ {n}_{w}$ = $\frac {4}{3}$ 

To find: Refractive index of air with respect to water, $_{w}\ {n}_{a}$.

Solution:

We know that the refractive index of a medium 1 with respect to medium 2 is reciprocal to the refractive index of medium 2 with respect to medium 1.

Therefore,

$Refractive\ index\ of\ air\ with\ respect\ to\ water\ (_{w}\ {n}_{a})=\frac {1}{Refractive\ index\ of\ water\ with\ respect\ to\ air(_{a}\ {n}_{w})}$

$_{w}\ {n}_{a}=\frac {1}{\frac {4}{3}}$

$_{w}\ {n}_{a}=\frac {3}{4}$

$_{w}\ {n}_{a}=0.75$

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Updated on: 10-Oct-2022

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