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The radius of a cone is $5\ cm$ and vertical height is $12\ cm$. Find the area of the curved surface.
Given:
The radius of a cone is $5\ cm$ and vertical height is $12\ cm$.
To do:
We have to find the area of the curved surface.
Solution:
Radius of the base of the cone $= 5\ cm$
Vertical height of the cone $(h) = 12\ cm$
This implies,
Slant height $(l)=\sqrt{r^{2}+h^{2}}$
$=\sqrt{(5)^{2}+(12)^{2}}$
$=\sqrt{25+144}$
$=\sqrt{169}$
$=13 \mathrm{~cm}$
Therefore,
The curved surface area of the cone $=\pi r l$
$=\frac{22}{7} \times 5 \times 13$
$=\frac{1430}{7}$
$=204.28 \mathrm{~cm}^{2}$
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