The points $A (x_1, y_1), B (x_2, y_2)$ and $C (x_3, y_3)$ are the vertices of $\triangle ABC$.
The median from $A$ meets $BC$ at $D$. Find the coordinates of the point $D$.

Given:

The points $A (x_1, y_1), B (x_2, y_2)$ and $C (x_3, y_3)$ are the vertices of $\triangle ABC$.

The median from $A$ meets $BC$ at $D$.

To do:

We have to find the coordinates of point $D$.

Solution:

$D$ is the mid-point of BC.

This implies,

Using mid-point formula, we get,

Coordinates of $D=(\frac{x_2+x_3}{2}, \frac{y_2+y_3}{2})$.

The coordinates of the point $D$ are $(\frac{x_2+x_3}{2}, \frac{y_2+y_3}{2})$ .

Tutorialspoint

Updated on: 10-Oct-2022

27 Views

Kickstart Your Career

Get certified by completing the course

Get Started