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The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of first triangle is 9 cm, what is the corresponding side of the other triangle?
Given:
The perimeters of two similar triangles are 25 cm and 15 cm respectively.
One side of first triangle is 9 cm.
To do:
We have to find the corresponding side of the other triangle.
Solution:
We know that,
In similar triangles, the perimeters of the triangles are in the ratio of their corresponding sides.
Let the corresponding side of the other triangle be $x$.
Therefore,
$\frac{25}{15}=\frac{9}{x}$
$25x=9\times15$ (On cross multiplication)
$x=\frac{135}{25}$
$x=\frac{27}{5}$
$x=5.4\ cm$
The corresponding side of the other triangle is 5.4 cm.
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