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The perimeter of a square is equal to the perimeter of the rectangle of length 16 cm and breadth 8 cm. Find the side of the square and area of the square.
Given:
The perimeter of a square is equal to the perimeter of the rectangle of length 16 cm and breadth 8 cm.
To do:
We have to find the side of the square and area of the square.
Solution:
Length of rectangle = 16 cm
Breadth = 8 cm
Perimeter of rectangle = 2 (length $+$ breadth)
Perimeter of rectangle = $2 ( 16 + 8)$
Perimeter of rectangle = $2(24)$
Perimeter of rectangle = 48 cm.
Perimeter of square = Perimeter of rectangle
Perimeter of square = 48 cm
Perimeter of square = 4 $\times$ side
48 = 4$\times$side
$\frac{48}{4}$ = side
Side = 12 cm
Side of the square is 12 cm.
Area of square = side $\times$ side
Area of square = 12 $\times$ 12 cm2
Area of the square is 144 sq.cm.
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