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The momentum of a bullet of mass 20 g fired from a gun is 10 kg m/s. The kinetic energy of this bullet in kJ will be:- 25
- 2.5
- 0.25
- 5
Mass of the fired bullet $m=20\ gm=\frac{20}{1000}=0.02\ kg$
The momentum of the bullet $P=10\ kg-m/s$
Therefore, the velocity of the bullet $v=\frac{P}{v}$
$=\frac{10}{0.02}\ m/s$
$=500\ m/s$
Therefore, kinetic energy $K=\frac{1}{2}\times0.2\times500^2$
$=25000\ J$
$=25\ KJ$
Therefore, option a). is correct.
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