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The longitudinal waves travel in a coiled spring at a rate of 4 m/s. The distance between two consecutive compressions is 20 cm. Find: (i) Wavelength of the wave (ii) Frequency of the wave
(i). The distance between two consecutive compressions or rarefactions is equal to its wavelength.
Hence, wavelength is$=20\ cm=0.20\ m$
(ii). Speed of wave $v=4\ m/s$
Wavelength $\lambda=0.20\ m$
Speed of wave$v=frequency(f)\times wavelength(\lambda)$
$4\ m/s=frequency(f)\times0.20\ m$
Or $frequency(f)=\frac{4}{0.20}$
Or $frequency(f)=20\ m/s$
Therefore, the frequency of the sound wave is $20\ m/s$.
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