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The length of a diagonal of a square is 8. Find the length of each side of the square.
Given:
The diagonal of a square is $8$ units.
To do:
We have to find the length of each side of the square.
Solution:
We know that,
Diagonal of a square of side $s$ is $\sqrt{2}s$.
Let the length of each side of the square be $s$.
This implies,
Diagonal of the given square $=\sqrt{2}s$.
Therefore,
$8=\sqrt{2}s$
$s=\frac{4\times2}{\sqrt2}$
$s=\frac{4\times\sqrt2\times\sqrt2}{\sqrt2}$
$s=4\sqrt2$
The length of each side of the square is $4\sqrt2$ units.
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