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The LC.M. and H.C.F. of two numbers are 720 and 5 respectively. If one of the two numbers is 45 find the other number.
Given :
The LCM and HCF of two numbers are 720 and 5 respectively.
One of the two numbers is 45.
To do :
We have to find the other number.
Solution :
Let the other number be 'a'.
We know that,
Product of two numbers $= HCF \times LCM$
Therefore,
$45 \times a = 720 \times 5$
$a = \frac{(720\times 5)}{45}$
$a = \frac{(720\times 1)}{9}$
$a = 80$.
The other number is 80.
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