The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, find the other.

Given: HCF of two numbers is 145 and their LCM is 2175. One number is 725.

To find: Here we have to find the second number other than 725 whose HCF and LCM is given.

Solution:

Let the required number be  $=$  a

Now, We know that:

LCM $\times$ HCF  $=$  Product of the two integers

So, 

2175 $\times$ 145  $=$  725 $\times$ a

315375  $=$  725a

a  $=\ \frac{315375}{725}$

a  $=$  435

So, the required number is 435.

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Updated on: 10-Oct-2022

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