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The following observations have been arranged in ascending order. If the median of the data is 63, find the value of $x: 29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$
Given:
$29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$
The median of the data is 63.
To do:
We have to find the value of $x$.
Solution:
We know that,
Median $= \frac{1}{2}[\frac{n}{2}th\ term+(\frac{n}{2}+1)th\ term]$ (when $n$ is even)
$=\frac{n+1}{2}th\ term$ (when $n$ is odd)
Here,
$n = 10$ which is even
Therefore,
Median $= \frac{1}{2}(x+x+2)$
$63= \frac{2x+2}{2}$
$63=x+1$
$x=63-1$
$x=62$
The value of $x$ is $62$.
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