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The focal length of a lens is +150 mm. What kind of lens is it and what is its power?
Given:
Focal length, $f$ = $+$150 mm = $+$0.15 m
To find: Kind of lens and its power, $P$.
Solution:
Power of a lens is given by:
$P=\frac {1}{f}$
Substituting the given values we get-
$P=\frac {1}{0.15}$
$P=\frac {100}{15}$
$P=+6.66D$
Thus, the power of the lens $P$ is 6.66 D, and the positive sign $(+)$ implies that the lens is convex in nature.
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