The dimensions of a room are $12.5\ m$ by $9\ m$ by $7\ m$. There are 2 doors and 4 windows in the room; each door measures $2.5\ m$ by $1.2\ m$ and each window $1.5\ m$ by $1\ m$. Find the cost of painting the walls at $Rs.\ 3.50$ per square metre.
Given:
The dimensions of a room are $12.5\ m$ by $9\ m$ by $7\ m$. There are 2 doors and 4 windows in the room; each door measures $2.5\ m$ by $1.2\ m$ and each window $1.5\ m$ by $1\ m$.
To do:
We have to find the cost of painting the walls at $Rs.\ 3.50$ per square metre.
Solution:
Length of the room $(l) = 12.5\ m$
Breadth of the room $(b) = 9\ m$
Height of the room $(h) = 7\ m$
Therefore,
Total area of walls $= 2h(l + b)$
$= 2 \times 7(12.5 + 9)$
$= 14 \times 21.5$
$= 301\ m^2$
Area of two doors of $2.5\ m \times 1.2\ m = 2 \times 2.5 \times 1.2$
$= 6\ m^2$
Area of four window of $1.5\ m \times 1\ m$
$= 4 \times 1.5 \times 1$
$= 6\ m^2$
Therefore,
Remaining area of the walls $= 301 - (6 + 6)$
$= 301 - 12$
$= 289\ m^2$
Rate of painting the walls $= Rs.\ 3.50$ per $m^2$
Total cost of painting $= 289 \times 3.50$
$= Rs.\ 1011.50$
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