The diagonals of a rhombus are of lengths $10\ cm$ and $8.2\ cm$. What will be area?


Given: The diagonals of a rhombus are of lengths $10\ cm$ and $8.2\ cm$.

To do: What will be area?

Solution:

Area of the rhombus $=\frac{1}{2}\times d_1\times d_2$

Where $d_1,\ d_2$ are lengths of diagonals

$=\frac{1}{2}\times 10\times 8.2\ cm^2$

 $=41\ cm^2$

Updated on: 10-Oct-2022

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