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The diagonals of a rhombus are of lengths $10\ cm$ and $8.2\ cm$. What will be area?
Given: The diagonals of a rhombus are of lengths $10\ cm$ and $8.2\ cm$.
To do: What will be area?
Solution:
Area of the rhombus $=\frac{1}{2}\times d_1\times d_2$
Where $d_1,\ d_2$ are lengths of diagonals
$=\frac{1}{2}\times 10\times 8.2\ cm^2$
$=41\ cm^2$
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