- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
The area of two similar triangles is $16\ cm^{2}$ and $25\ cm^{2}$. Find the ratio of their corresponding altitudes.
Given: The area of two similar triangles is $16\ cm^{2}$ and $25\ cm^{2}$.
To do: To find the ratio of their corresponding altitudes.
Solution:
Let the corresponding sides of the triangles be $x$ and $y$.
As known, $\frac{Area( 1st\ triangle)}{Area( 2nd\ triangle)} =$ Square of ratio of corresponding sides
$\Rightarrow \frac{16}{25}=( \frac{x}{y})^{2}$
$\Rightarrow \frac{x}{y}=\sqrt{\frac{16}{25}}$
$\Rightarrow \frac{x}{y}=\frac{4}{5}$
$\Rightarrow x:y=4:5$
Therefore, the ratio of the corresponding altitudes is $4:5$.
Advertisements