Teachers and students are selected at random to make two teams of $20$ members each on sports day to participate in the event of Tug of War". The numbers of volunteers are as follows:

Teacher

Student

Male	Female	Male	Female
12	18	20	10

Find the probability that the person chosen at random."

Given: Teachers and students are selected at random to make two teams of $30$ members each on sports day to participate in the event of "Tug of War". The numbers of volunteers are given in the table.

To do: To find the probability that the person chosen at random:

$( i)$. is a male.

$( ii)$. is a female student.

Solution:

As given in the table:

Number of male teacher $=12$

Number female teachers $=18$

Number of male students $=20$

Number of female students $=10$

Total number of outcomes$=12+18+20+10=60$

$( i)$. Number of male teachers $=12$

Therefore, probability of a male teacher to be chosen$=\frac{Total\ no.\ of\ favorable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

$=\frac{12}{60}$

$=\frac{1}{5}$

Thus, the probability of being chosen a male teacher is $\frac{1}{5}$.

$( ii)$.  Number of female student$=10$

Therefore, probability of a female student to be chosen$=\frac{Total\ no.\ of\ favorable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

$=\frac{10}{60}$

$=\frac{1}{6}$

Thus, the probability of being chosen a female student is $\frac{1}{5}$.

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Updated on: 10-Oct-2022

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