Taylor purchased a rectangular plot of area $634m^2$. The length of plot is 2 more than thrice of its breadth. Find the length and breadth. (approximate value)
Given :
Taylor purchased a rectangular plot of area $634m^2$.
The length of the plot is 2 m more than the thrice of its breadth.
To find :
We have to find the length and breadth of the rectangle.
Solution :
Let the breadth of the plot be $x$ m.
The length of the plot $= x+2$ m.
Area of a rectangle of length l and breadth b is $l \times b$.
Therefore,
$634 m^2 = (x)(x+2) m^2$
$634 = x^2+2x$
$x^2+2x-634 = 0$
$ x=\frac{-2\pm \sqrt{2^{2} -4\times 1\times ( -634)}}{2( 1)}$
$x=\frac{-2\pm \sqrt{4+2536}}{2}$
$x=\frac{-2\pm \sqrt{2540}}{2}$
$x=-1\pm \sqrt{635}$
$x=-1\pm 25$
$x=24$
The breadth of the rectangular plot is 24 m(approx.)
The length of the rectangular plot is 24+2 m = 26 m(approx.)
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