Sum of two numbers is 95. If one exceeds the other number by 37. Find the numbers.
 


Given: Sum of two numbers is 95 and one exceeds the other number by 37.

To find: We have to find the numbers.


Solution: 

Let the smaller number be = a

So, the greater number be = a $+$ 37

Now, given that:

Sum of these two numbers = 95

(a) $+$ $( a\ +\ 37)$ = 95

2a $+$ 37 = 95

2a = 95 $-$ 37

2a = 58

a = $\frac{58}{2}$

a = 29

Therefore,

The smaller number = a = 29

The greater number = a $+$ 37 = 29 $+$ 37 = 66

So, the two numbers are 29 and 66.

Updated on: 10-Oct-2022

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