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Subtract $3x - 4y - 7z$ from the sum of $x - 3y + 2z$ and $-4x + 9y- 11z$.
To do:
We have to subtract $3x - 4y - 7z$ from the sum of $x - 3y + 2z$ and $-4x + 9y- 11z$.
Solution:
Sum of $x - 3y + 2z$ and $-4x + 9y - 11z$ is,
$x - 3y + 2z + (- 4x + 9y - 11z) = x - 3y + 2z - 4x + 9y - 11z$
$= x - 4x - 3y + 9y + 2z - 11z$
$= -3x + 6y - 9z$
Subtracting $3x - 4y - 7z$ from $(-3x + 6y - 9z)$
$(-3x + 6y - 9z)-(3x - 4y - 7z)=-3x + 6y - 9z - 3x + 4y + 7z$
$= -3x - 3x + 6y + 4y -9z +7z$
$= -6x + 10y - 2z$
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