Solve the following system of equations:

$\sqrt{2}x\ –\ \sqrt{3}y\ =\ 0$
$\sqrt{3}x\ −\ \sqrt{8}y\ =\ 0$

Given: The pair of linear equation are  $\sqrt{2}x\ –\ \sqrt{3}y\ =\ 0$ ;

$\sqrt{3}x\ −\ \sqrt{8}y\ =\ 0$

To do: Solve the system of equations

Solution:

The given pair of equations are:

 $\sqrt{2}x\ –\ \sqrt{3}y\ =\ 0$=
0…………i)

$\sqrt{3}x\ −\ \sqrt{8}y\ =\ 0$…………ii) 

From equation i) $ x = \sqrt(\frac{3}{2})y$ ……………..iii)

Substituting this value in equation ii) we obtain

$\sqrt{3}x\ −\ \sqrt{8}y\ =\ 0$

$\Rightarrow \sqrt{3}\left(\sqrt{\frac{3}{2}}\right) -\sqrt{8} y=0$

$\Rightarrow \frac{3}{\sqrt{2}} -8y=0$

$\Rightarrow 3y-4y = 0$

$\Rightarrow y=0$

Now, substituting y in equation iii) we obtain 

$\Rightarrow x = 0$ 

Thus, the value of $x$ and $y$ obtained are $0$ and $0 $respectively  

Tutorialspoint

Updated on: 10-Oct-2022

275 Views

Kickstart Your Career

Get certified by completing the course

Get Started