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Solve the following $Sin^2 60° + Cos^2 60°$
Given: $Sin^2 60° + Cos^2 60°$
To find: The value of the expression
Solution:
$Sin^2 60° + Cos^2 60°$
=$(\frac{\sqrt{3}}{2})^2 +(\frac{1}{2})^2$
=$\frac{3}{4}+\frac{1}{4}$
=$\frac{4}{4}=1$
Hence the value of $Sin^2 60° + Cos^2 60°$ is $1$
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